What is the general solution for cos^2(150)-sin^2(150)=tan(x) ?

The general solution for cos^2(150)-sin^2(150)=tan(x) is x=0.46364…+180n

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Popular Trigonometry >

cos^2(150)-sin^2(150)=tan(x)

Solution

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ}) = tan (x)

Solution

x = 0.46364 \dots + 18 0^{\circ} n

Radians

x = 0.46364 \dots + πn

Solution steps

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ}) = tan (x)

cos (15 0^{\circ}) = - \frac{3}{2}

cos (15 0^{\circ})

Use the following trivial identity:

cos (15 0^{\circ}) = - \frac{3}{2}

cos (15 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{3}{2}

= - \frac{3}{2}

sin (15 0^{\circ}) = \frac{1}{2}

sin (15 0^{\circ})

Use the following trivial identity:

sin (15 0^{\circ}) = \frac{1}{2}

sin (15 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} = tan (x)

Switch sides

tan (x) = (- \frac{3}{2})^{2} - (\frac{1}{2})^{2}

Simplify

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} : \frac{1}{2}

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2}

(- \frac{3}{2})^{2} = \frac{3}{2 ^{2}}

(- \frac{3}{2})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2})^{2} = (\frac{3}{2})^{2}

= (\frac{3}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{2 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{3}{2 ^{2}}

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= \frac{3}{2 ^{2}} - \frac{1}{2 ^{2}}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 - 1}{2 ^{2}}

Subtract the numbers:

3 - 1 = 2

= \frac{2}{2 ^{2}}

Cancel the common factor:

2

= \frac{1}{2}

Apply trig inverse properties

tan (x) = \frac{1}{2}

General solutions for

tan (x) = \frac{1}{2}

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

x = arctan (\frac{1}{2}) + 18 0^{\circ} n

x = arctan (\frac{1}{2}) + 18 0^{\circ} n

Show solutions in decimal form

x = 0.46364 \dots + 18 0^{\circ} n

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for cos^2(150)-sin^2(150)=tan(x) ?
The general solution for cos^2(150)-sin^2(150)=tan(x) is x=0.46364…+180n