What is the general solution for 1.5sin(30)=sin(x) ?

The general solution for 1.5sin(30)=sin(x) is x=0.84806…+360n,x=180-0.84806…+360n

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1.5sin(30)=sin(x)

1.5 sin (3 0^{\circ}) = sin (x)

x = 0.84806 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.84806 \dots + 36 0^{\circ} n

Radians

x = 0.84806 \dots + 2 πn, x = π - 0.84806 \dots + 2 πn

Solution steps

1.5 sin (3 0^{\circ}) = sin (x)

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

1.5 \cdot \frac{1}{2} = sin (x)

Switch sides

sin (x) = 1.5 \cdot \frac{1}{2}

Simplify

1.5 \cdot \frac{1}{2} : \frac{1.5}{2}

1.5 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 1.5}{2}

Multiply the numbers:

1 \cdot 1.5 = 1.5

= \frac{1.5}{2}

Apply trig inverse properties

sin (x) = \frac{1.5}{2}

General solutions for

sin (x) = \frac{1.5}{2}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (\frac{1.5}{2}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{1.5}{2}) + 36 0^{\circ} n

x = arcsin (\frac{1.5}{2}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{1.5}{2}) + 36 0^{\circ} n

Show solutions in decimal form

x = 0.84806 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.84806 \dots + 36 0^{\circ} n

What is the general solution for 1.5sin(30)=sin(x) ?
The general solution for 1.5sin(30)=sin(x) is x=0.84806…+360n,x=180-0.84806…+360n