cos(θ)=0.6798,0<= θ<= 360

解

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 0.82330 \dots, θ = 5.45987 \dots

解答ステップ

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

三角関数の逆数プロパティを適用する

cos (θ) = 0.6798

以下の一般解

cos (θ) = 0.6798

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (0.6798) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (0.6798) + 36 0^{\circ} n

θ = arccos (0.6798) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (0.6798) + 36 0^{\circ} n

範囲の解答

0 \leq θ \leq 36 0^{\circ}

θ = 0.82330 \dots, θ = 5.45987 \dots