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受欢迎的三角函数 >

5tan^2(t)-tan(t)=0

解答

5 tan^{2} (t) - tan (t) = 0

解答

t = 0.19739 \dots + πn, t = πn

+1

度数

t = 11.30993 \dots^{\circ} + 18 0^{\circ} n, t = 0^{\circ} + 18 0^{\circ} n

求解步骤

5 tan^{2} (t) - tan (t) = 0

用替代法求解

5 tan^{2} (t) - tan (t) = 0

令

: tan (t) = u

5 u^{2} - u = 0

5 u^{2} - u = 0 : u = \frac{1}{5}, u = 0

5 u^{2} - u = 0

使用求根公式求解

5 u^{2} - u = 0

二次方程求根公式:

若

a = 5, b = - 1, c = 0

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 \cdot 0 = 1

(- 1)^{2} - 4 \cdot 5 \cdot 0

(- 1)^{2} = 1

(- 1)^{2}

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 1)^{2} = 1^{2}

= 1^{2}

使用法则

1^{a} = 1

= 1

4 \cdot 5 \cdot 0 = 0

4 \cdot 5 \cdot 0

使用法则

0 \cdot a = 0

= 0

= 1 - 0

数字相减:

1 - 0 = 1

= 1

使用法则

1 = 1

= 1

u_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 5}

将解分隔开

u_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 5}, u_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 5}

u = \frac{- ( - 1 ) + 1}{2 \cdot 5} : \frac{1}{5}

\frac{- ( - 1 ) + 1}{2 \cdot 5}

使用法则

- (- a) = a

= \frac{1 + 1}{2 \cdot 5}

数字相加:

1 + 1 = 2

= \frac{2}{2 \cdot 5}

数字相乘:

2 \cdot 5 = 10

= \frac{2}{10}

约分:

2

= \frac{1}{5}

u = \frac{- ( - 1 ) - 1}{2 \cdot 5} : 0

\frac{- ( - 1 ) - 1}{2 \cdot 5}

使用法则

- (- a) = a

= \frac{1 - 1}{2 \cdot 5}

数字相减:

1 - 1 = 0

= \frac{0}{2 \cdot 5}

数字相乘:

2 \cdot 5 = 10

= \frac{0}{10}

使用法则

\frac{0}{a} = 0, a \neq = 0

= 0

二次方程组的解是:

u = \frac{1}{5}, u = 0

u = tan (t)

代回

tan (t) = \frac{1}{5}, tan (t) = 0

tan (t) = \frac{1}{5}, tan (t) = 0

tan (t) = \frac{1}{5} : t = arctan (\frac{1}{5}) + πn

tan (t) = \frac{1}{5}

使用反三角函数性质

tan (t) = \frac{1}{5}

tan (t) = \frac{1}{5}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

t = arctan (\frac{1}{5}) + πn

t = arctan (\frac{1}{5}) + πn

tan (t) = 0 : t = πn

tan (t) = 0

tan (t) = 0

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

t = 0 + πn

t = 0 + πn

解

t = 0 + πn : t = πn

t = 0 + πn

0 + πn = πn

t = πn

t = πn

合并所有解

t = arctan (\frac{1}{5}) + πn, t = πn

以小数形式表示解

t = 0.19739 \dots + πn, t = πn

作图

流行的例子

sin (x) = \frac{9}{16}

24=32+8-2*sqrt(32*8)*cos(θ)

24 = 32 + 8 - 2 \cdot 32 \cdot 8 \cdot cos (θ)

sin(45+a)cos(45+a)=(sqrt(2))/2

sin (4 5^{\circ} + a) cos (4 5^{\circ} + a) = \frac{2}{2}

sin (z) = 2

sin (x) = \frac{9}{10}