tan(x)=sqrt(3),-180<x<180

Lösung

tan (x) = 3, - 18 0^{\circ} < x < 18 0^{\circ}

x = 6 0^{\circ}, x = - 12 0^{\circ}

Radianten

x = \frac{π}{3}, x = - \frac{2 π}{3}

Schritte zur Lösung

tan (x) = 3, - 18 0^{\circ} < x < 18 0^{\circ}

Allgemeine Lösung für

tan (x) = 3

tan (x)

Periodizitätstabelle mit

18 0^{\circ} n

Zyklus:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 6 0^{\circ} + 18 0^{\circ} n

x = 6 0^{\circ} + 18 0^{\circ} n

Lösungen für den Bereich

- 18 0^{\circ} < x < 18 0^{\circ}

x = 6 0^{\circ}, x = - 12 0^{\circ}

cot^{2} (t) csc (t) = sin (t)

\frac{6}{12} = cos (θ)

sin (a) = \frac{6.88}{6.9}

sin (x) = cos (3 2^{\circ})

so l v e f or x, y = cos (4 x)