해법
88.2sin(x)−12.78=0.1⋅88.2cos(x)
해법
x=0.24435…+2πn,x=π−0.04501…+2πn
+1
도
x=14.00032…∘+360∘n,x=177.42086…∘+360∘n솔루션 단계
88.2sin(x)−12.78=0.1⋅88.2cos(x)
양쪽을 제곱(88.2sin(x)−12.78)2=(0.1⋅88.2cos(x))2
빼다 (0.188.2cos(x))2 양쪽에서(88.2sin(x)−12.78)2−77.7924cos2(x)=0
삼각성을 사용하여 다시 쓰기
(−12.78+88.2sin(x))2−77.7924cos2(x)
피타고라스 정체성 사용: cos2(x)+sin2(x)=1cos2(x)=1−sin2(x)=(−12.78+88.2sin(x))2−77.7924(1−sin2(x))
(−12.78+88.2sin(x))2−77.7924(1−sin2(x))간소화하다 :7857.0324sin2(x)−2254.392sin(x)+85.536
(−12.78+88.2sin(x))2−77.7924(1−sin2(x))
(−12.78+88.2sin(x))2:163.3284−2254.392sin(x)+7779.24sin2(x)
완벽한 정사각형 공식 적용: (a+b)2=a2+2ab+b2a=−12.78,b=88.2sin(x)
=(−12.78)2+2(−12.78)⋅88.2sin(x)+(88.2sin(x))2
(−12.78)2+2(−12.78)⋅88.2sin(x)+(88.2sin(x))2단순화하세요:163.3284−2254.392sin(x)+7779.24sin2(x)
(−12.78)2+2(−12.78)⋅88.2sin(x)+(88.2sin(x))2
괄호 제거: (−a)=−a=(−12.78)2−2⋅12.78⋅88.2sin(x)+(88.2sin(x))2
(−12.78)2=163.3284
(−12.78)2
지수 규칙 적용: (−a)n=an,이면 n 균등하다(−12.78)2=12.782=12.782
12.782=163.3284=163.3284
2⋅12.78⋅88.2sin(x)=2254.392sin(x)
2⋅12.78⋅88.2sin(x)
숫자를 곱하시오: 2⋅12.78⋅88.2=2254.392=2254.392sin(x)
(88.2sin(x))2=7779.24sin2(x)
(88.2sin(x))2
지수 규칙 적용: (a⋅b)n=anbn=88.22sin2(x)
88.22=7779.24=7779.24sin2(x)
=163.3284−2254.392sin(x)+7779.24sin2(x)
=163.3284−2254.392sin(x)+7779.24sin2(x)
=163.3284−2254.392sin(x)+7779.24sin2(x)−77.7924(1−sin2(x))
−77.7924(1−sin2(x))확대한다:−77.7924+77.7924sin2(x)
−77.7924(1−sin2(x))
분배 법칙 적용: a(b−c)=ab−aca=−77.7924,b=1,c=sin2(x)=−77.7924⋅1−(−77.7924)sin2(x)
마이너스 플러스 규칙 적용−(−a)=a=−1⋅77.7924+77.7924sin2(x)
숫자를 곱하시오: 1⋅77.7924=77.7924=−77.7924+77.7924sin2(x)
=163.3284−2254.392sin(x)+7779.24sin2(x)−77.7924+77.7924sin2(x)
163.3284−2254.392sin(x)+7779.24sin2(x)−77.7924+77.7924sin2(x)단순화하세요:7857.0324sin2(x)−2254.392sin(x)+85.536
163.3284−2254.392sin(x)+7779.24sin2(x)−77.7924+77.7924sin2(x)
집단적 용어=−2254.392sin(x)+7779.24sin2(x)+77.7924sin2(x)+163.3284−77.7924
유사 요소 추가: 7779.24sin2(x)+77.7924sin2(x)=7857.0324sin2(x)=−2254.392sin(x)+7857.0324sin2(x)+163.3284−77.7924
숫자 더하기/ 빼기: 163.3284−77.7924=85.536=7857.0324sin2(x)−2254.392sin(x)+85.536
=7857.0324sin2(x)−2254.392sin(x)+85.536
=7857.0324sin2(x)−2254.392sin(x)+85.536
85.536−2254.392sin(x)+7857.0324sin2(x)=0
대체로 해결
85.536−2254.392sin(x)+7857.0324sin2(x)=0
하게: sin(x)=u85.536−2254.392u+7857.0324u2=0
85.536−2254.392u+7857.0324u2=0:u=20.28692…+0.03878…,u=20.28692…−0.03878…
85.536−2254.392u+7857.0324u2=0
양쪽을 다음으로 나눕니다 7857.03247857.032485.536−7857.03242254.392u+7857.03247857.0324u2=7857.03240
표준 양식으로 작성 ax2+bx+c=0u2−0.28692…u+0.01088…=0
쿼드 공식으로 해결
u2−0.28692…u+0.01088…=0
4차 방정식 공식:
위해서 a=1,b=−0.28692…,c=0.01088…u1,2=2⋅1−(−0.28692…)±(−0.28692…)2−4⋅1⋅0.01088…
u1,2=2⋅1−(−0.28692…)±(−0.28692…)2−4⋅1⋅0.01088…
(−0.28692…)2−4⋅1⋅0.01088…=0.03878…
(−0.28692…)2−4⋅1⋅0.01088…
지수 규칙 적용: (−a)n=an,이면 n 균등하다(−0.28692…)2=0.28692…2=0.28692…2−4⋅1⋅0.01088…
숫자를 곱하시오: 4⋅1⋅0.01088…=0.04354…=0.28692…2−0.04354…
0.28692…2=0.08232…=0.08232…−0.04354…
숫자를 빼세요: 0.08232…−0.04354…=0.03878…=0.03878…
u1,2=2⋅1−(−0.28692…)±0.03878…
솔루션 분리u1=2⋅1−(−0.28692…)+0.03878…,u2=2⋅1−(−0.28692…)−0.03878…
u=2⋅1−(−0.28692…)+0.03878…:20.28692…+0.03878…
2⋅1−(−0.28692…)+0.03878…
규칙 적용 −(−a)=a=2⋅10.28692…+0.03878…
숫자를 곱하시오: 2⋅1=2=20.28692…+0.03878…
u=2⋅1−(−0.28692…)−0.03878…:20.28692…−0.03878…
2⋅1−(−0.28692…)−0.03878…
규칙 적용 −(−a)=a=2⋅10.28692…−0.03878…
숫자를 곱하시오: 2⋅1=2=20.28692…−0.03878…
2차 방정식의 해는 다음과 같다:u=20.28692…+0.03878…,u=20.28692…−0.03878…
뒤로 대체 u=sin(x)sin(x)=20.28692…+0.03878…,sin(x)=20.28692…−0.03878…
sin(x)=20.28692…+0.03878…,sin(x)=20.28692…−0.03878…
sin(x)=20.28692…+0.03878…:x=arcsin(20.28692…+0.03878…)+2πn,x=π−arcsin(20.28692…+0.03878…)+2πn
sin(x)=20.28692…+0.03878…
트리거 역속성 적용
sin(x)=20.28692…+0.03878…
일반 솔루션 sin(x)=20.28692…+0.03878…sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πnx=arcsin(20.28692…+0.03878…)+2πn,x=π−arcsin(20.28692…+0.03878…)+2πn
x=arcsin(20.28692…+0.03878…)+2πn,x=π−arcsin(20.28692…+0.03878…)+2πn
sin(x)=20.28692…−0.03878…:x=arcsin(20.28692…−0.03878…)+2πn,x=π−arcsin(20.28692…−0.03878…)+2πn
sin(x)=20.28692…−0.03878…
트리거 역속성 적용
sin(x)=20.28692…−0.03878…
일반 솔루션 sin(x)=20.28692…−0.03878…sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πnx=arcsin(20.28692…−0.03878…)+2πn,x=π−arcsin(20.28692…−0.03878…)+2πn
x=arcsin(20.28692…−0.03878…)+2πn,x=π−arcsin(20.28692…−0.03878…)+2πn
모든 솔루션 결합x=arcsin(20.28692…+0.03878…)+2πn,x=π−arcsin(20.28692…+0.03878…)+2πn,x=arcsin(20.28692…−0.03878…)+2πn,x=π−arcsin(20.28692…−0.03878…)+2πn
해법을 원래 방정식에 연결하여 검증
솔루션을 에 연결하여 확인합니다 88.2sin(x)−12.78=0.188.2cos(x)
방정식에 맞지 않는 것은 제거하십시오.
솔루션 확인 arcsin(20.28692…+0.03878…)+2πn:참
arcsin(20.28692…+0.03878…)+2πn
n=1끼우다 arcsin(20.28692…+0.03878…)+2π1
88.2sin(x)−12.78=0.188.2cos(x) 위한 {\ quad}끼우다{\ quad} x=arcsin(20.28692…+0.03878…)+2π188.2sin(arcsin(20.28692…+0.03878…)+2π1)−12.78=0.1⋅88.2cos(arcsin(20.28692…+0.03878…)+2π1)
다듬다8.55799…=8.55799…
⇒참
솔루션 확인 π−arcsin(20.28692…+0.03878…)+2πn:거짓
π−arcsin(20.28692…+0.03878…)+2πn
n=1끼우다 π−arcsin(20.28692…+0.03878…)+2π1
88.2sin(x)−12.78=0.188.2cos(x) 위한 {\ quad}끼우다{\ quad} x=π−arcsin(20.28692…+0.03878…)+2π188.2sin(π−arcsin(20.28692…+0.03878…)+2π1)−12.78=0.1⋅88.2cos(π−arcsin(20.28692…+0.03878…)+2π1)
다듬다8.55799…=−8.55799…
⇒거짓
솔루션 확인 arcsin(20.28692…−0.03878…)+2πn:거짓
arcsin(20.28692…−0.03878…)+2πn
n=1끼우다 arcsin(20.28692…−0.03878…)+2π1
88.2sin(x)−12.78=0.188.2cos(x) 위한 {\ quad}끼우다{\ quad} x=arcsin(20.28692…−0.03878…)+2π188.2sin(arcsin(20.28692…−0.03878…)+2π1)−12.78=0.1⋅88.2cos(arcsin(20.28692…−0.03878…)+2π1)
다듬다−8.81106…=8.81106…
⇒거짓
솔루션 확인 π−arcsin(20.28692…−0.03878…)+2πn:참
π−arcsin(20.28692…−0.03878…)+2πn
n=1끼우다 π−arcsin(20.28692…−0.03878…)+2π1
88.2sin(x)−12.78=0.188.2cos(x) 위한 {\ quad}끼우다{\ quad} x=π−arcsin(20.28692…−0.03878…)+2π188.2sin(π−arcsin(20.28692…−0.03878…)+2π1)−12.78=0.1⋅88.2cos(π−arcsin(20.28692…−0.03878…)+2π1)
다듬다−8.81106…=−8.81106…
⇒참
x=arcsin(20.28692…+0.03878…)+2πn,x=π−arcsin(20.28692…−0.03878…)+2πn
해를 10진수 형식으로 표시x=0.24435…+2πn,x=π−0.04501…+2πn