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受欢迎的三角函数 >

tan(45+x/3)=0.58

解答

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

解答

x = 3 \cdot 0.52558 \dots + 54 0^{\circ} n - 13 5^{\circ}

+1

弧度

x = 3 \cdot 0.52558 \dots - \frac{3 π}{4} + 3 πn

求解步骤

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

使用反三角函数性质

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

的通解

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

解

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n : x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

将

4 5^{\circ}

到右边

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

两边减去

4 5^{\circ}

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

化简

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

在两边乘以

3

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

在两边乘以

3

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

化简

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

化简

\frac{3 x}{3} : x

\frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ} : 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

乘

3 \cdot 4 5^{\circ} : 13 5^{\circ}

3 \cdot 4 5^{\circ}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 13 5^{\circ}

= 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

以小数形式表示解

x = 3 \cdot 0.52558 \dots + 54 0^{\circ} n - 13 5^{\circ}

作图

流行的例子

r = a (1 + sin (x))

tan(Θ)=1.4,180<,Θ<270

tan (Θ) = 1.4, 18 0^{\circ} <, Θ < 27 0^{\circ}

(1+4cos(θ))^2=(sqrt(3)sin(θ))

(1 + 4 cos (θ))^{2} = (3 sin (θ))

sin(θ)-(cos(θ))/5 =0.6377

sin (θ) - \frac{cos ( θ )}{5} = 0.6377

sin(4x)=cos(4x)

sin (4 x) = cos (4 x)