解答
sin(120⋅π⋅t)=0.06141
解答
t=120π0.06144…+60n,t=1201−120π0.06144…+60n
+1
度数
t=0.00933…∘+0.95492…∘n,t=0.46812…∘+0.95492…∘n求解步骤
sin(120πt)=0.06141
使用反三角函数性质
sin(120πt)=0.06141
sin(120πt)=0.06141的通解sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πn120πt=arcsin(0.06141)+2πn,120πt=π−arcsin(0.06141)+2πn
120πt=arcsin(0.06141)+2πn,120πt=π−arcsin(0.06141)+2πn
解 120πt=arcsin(0.06141)+2πn:t=120πarcsin(0.06141)+60n
120πt=arcsin(0.06141)+2πn
两边除以 120π
120πt=arcsin(0.06141)+2πn
两边除以 120π120π120πt=120πarcsin(0.06141)+120π2πn
化简
120π120πt=120πarcsin(0.06141)+120π2πn
化简 120π120πt:t
120π120πt
数字相除:120120=1=ππt
约分:π=t
化简 120πarcsin(0.06141)+120π2πn:120πarcsin(0.06141)+60n
120πarcsin(0.06141)+120π2πn
消掉 120π2πn:60n
120π2πn
消掉 120π2πn:60n
120π2πn
约分:2=60ππn
约分:π=60n
=60n
=120πarcsin(0.06141)+60n
t=120πarcsin(0.06141)+60n
t=120πarcsin(0.06141)+60n
t=120πarcsin(0.06141)+60n
解 120πt=π−arcsin(0.06141)+2πn:t=1201−120πarcsin(0.06141)+60n
120πt=π−arcsin(0.06141)+2πn
两边除以 120π
120πt=π−arcsin(0.06141)+2πn
两边除以 120π120π120πt=120ππ−120πarcsin(0.06141)+120π2πn
化简
120π120πt=120ππ−120πarcsin(0.06141)+120π2πn
化简 120π120πt:t
120π120πt
数字相除:120120=1=ππt
约分:π=t
化简 120ππ−120πarcsin(0.06141)+120π2πn:1201−120πarcsin(0.06141)+60n
120ππ−120πarcsin(0.06141)+120π2πn
消掉 120ππ:1201
120ππ
约分:π=1201
=1201−120πarcsin(0.06141)+120π2πn
消掉 120π2πn:60n
120π2πn
消掉 120π2πn:60n
120π2πn
约分:2=60ππn
约分:π=60n
=60n
=1201−120πarcsin(0.06141)+60n
t=1201−120πarcsin(0.06141)+60n
t=1201−120πarcsin(0.06141)+60n
t=1201−120πarcsin(0.06141)+60n
t=120πarcsin(0.06141)+60n,t=1201−120πarcsin(0.06141)+60n
以小数形式表示解t=120π0.06144…+60n,t=1201−120π0.06144…+60n