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受欢迎的三角函数 >

8tan(a)+3=2tan(a)+3

解答

8 tan (a) + 3 = 2 tan (a) + 3

解答

a = πn

+1

度数

a = 0^{\circ} + 18 0^{\circ} n

求解步骤

8 tan (a) + 3 = 2 tan (a) + 3

用替代法求解

8 tan (a) + 3 = 2 tan (a) + 3

令

: tan (a) = u

8 u + 3 = 2 u + 3

8 u + 3 = 2 u + 3 : u = 0

8 u + 3 = 2 u + 3

两边减去

3

8 u + 3 - 3 = 2 u + 3 - 3

化简

8 u = 2 u

将

2 u

para o lado esquerdo

8 u = 2 u

两边减去

2 u

8 u - 2 u = 2 u - 2 u

化简

6 u = 0

6 u = 0

两边除以

6

6 u = 0

两边除以

6

\frac{6 u}{6} = \frac{0}{6}

化简

u = 0

u = 0

u = tan (a)

代回

tan (a) = 0

tan (a) = 0

tan (a) = 0 : a = πn

tan (a) = 0

tan (a) = 0

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

a = 0 + πn

a = 0 + πn

解

a = 0 + πn : a = πn

a = 0 + πn

0 + πn = πn

a = πn

a = πn

合并所有解

a = πn

作图

流行的例子

tan(θ/2)=(sqrt(3))/3

tan (\frac{θ}{2}) = \frac{3}{3}

solvefor x,cos(x)+1=0

so l v e f or x, cos (x) + 1 = 0

- 8 sin (x) = 0

sin (θ + \frac{π}{4}) = 0

2sin^2(x)-7sin(x)+3=0,0<= x<= 2pi

2 sin^{2} (x) - 7 sin (x) + 3 = 0, 0 \leq x \leq 2 π