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受欢迎的三角函数 >

sin(pi/2-x)=-1,0<= x<= 360

解答

sin (\frac{π}{2} - x) = - 1, 0^{\circ} \leq x \leq 36 0^{\circ}

解答

x = 18 0^{\circ}

+1

弧度

x = π

求解步骤

sin (\frac{π}{2} - x) = - 1, 0^{\circ} \leq x \leq 36 0^{\circ}

sin (9 0^{\circ} - x) = - 1

的通解

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

9 0^{\circ} - x = 27 0^{\circ} + 36 0^{\circ} n

9 0^{\circ} - x = 27 0^{\circ} + 36 0^{\circ} n

解

9 0^{\circ} - x = 27 0^{\circ} + 36 0^{\circ} n : x = - 36 0^{\circ} n - 18 0^{\circ}

9 0^{\circ} - x = 27 0^{\circ} + 36 0^{\circ} n

将

9 0^{\circ}

到右边

9 0^{\circ} - x = 27 0^{\circ} + 36 0^{\circ} n

两边减去

9 0^{\circ}

9 0^{\circ} - x - 9 0^{\circ} = 27 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ}

化简

9 0^{\circ} - x - 9 0^{\circ} = 27 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ}

化简

9 0^{\circ} - x - 9 0^{\circ} : - x

9 0^{\circ} - x - 9 0^{\circ}

同类项相加:

9 0^{\circ} - 9 0^{\circ} = 0

= - x

化简

27 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ} : 36 0^{\circ} n + 18 0^{\circ}

27 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ}

对同类项分组

= 36 0^{\circ} n - 9 0^{\circ} + 27 0^{\circ}

合并分式

- 9 0^{\circ} + 27 0^{\circ} : 18 0^{\circ}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} + 54 0 ^{\circ}}{2}

同类项相加:

- 18 0^{\circ} + 54 0^{\circ} = 36 0^{\circ}

= 18 0^{\circ}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ}

= 36 0^{\circ} n + 18 0^{\circ}

- x = 36 0^{\circ} n + 18 0^{\circ}

- x = 36 0^{\circ} n + 18 0^{\circ}

- x = 36 0^{\circ} n + 18 0^{\circ}

两边除以

- 1

- x = 36 0^{\circ} n + 18 0^{\circ}

两边除以

- 1

\frac{- x}{- 1} = \frac{36 0 ^{\circ} n}{- 1} + \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} = \frac{36 0 ^{\circ} n}{- 1} + \frac{18 0 ^{\circ}}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{36 0 ^{\circ} n}{- 1} + \frac{18 0 ^{\circ}}{- 1} : - 36 0^{\circ} n - 18 0^{\circ}

\frac{36 0 ^{\circ} n}{- 1} + \frac{18 0 ^{\circ}}{- 1}

\frac{36 0 ^{\circ} n}{- 1} = - 36 0^{\circ} n

\frac{36 0 ^{\circ} n}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{36 0 ^{\circ} n}{1}

使用法则

\frac{a}{1} = a

= - 36 0^{\circ} n

= - 36 0^{\circ} n + \frac{18 0 ^{\circ}}{- 1}

\frac{18 0 ^{\circ}}{- 1} = - 18 0^{\circ}

\frac{18 0 ^{\circ}}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - 18 0^{\circ}

使用法则

\frac{a}{1} = a

= - 18 0^{\circ}

= - 36 0^{\circ} n - 18 0^{\circ}

x = - 36 0^{\circ} n - 18 0^{\circ}

x = - 36 0^{\circ} n - 18 0^{\circ}

x = - 36 0^{\circ} n - 18 0^{\circ}

x = - 36 0^{\circ} n - 18 0^{\circ}

在

0 \leq x \leq 36 0^{\circ}

范围内的解

x = 18 0^{\circ}

作图

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