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受欢迎的 三角函数 >

tan(x)+2cos(x)csc(x)=sec(x)cos(x)+cot(x)

  • 初等代数
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  • 统计
  • 化学

解答

tan(x)+2cos(x)csc(x)=sec(x)cos(x)+cot(x)

解答

x∈R无解
求解步骤
tan(x)+2cos(x)csc(x)=sec(x)cos(x)+cot(x)
两边减去 sec(x)cos(x)+cot(x)tan(x)+2cos(x)csc(x)−sec(x)cos(x)−cot(x)=0
用 sin, cos 表示
−cot(x)+tan(x)−cos(x)sec(x)+2cos(x)csc(x)
使用基本三角恒等式: cot(x)=sin(x)cos(x)​=−sin(x)cos(x)​+tan(x)−cos(x)sec(x)+2cos(x)csc(x)
使用基本三角恒等式: tan(x)=cos(x)sin(x)​=−sin(x)cos(x)​+cos(x)sin(x)​−cos(x)sec(x)+2cos(x)csc(x)
使用基本三角恒等式: sec(x)=cos(x)1​=−sin(x)cos(x)​+cos(x)sin(x)​−cos(x)cos(x)1​+2cos(x)csc(x)
使用基本三角恒等式: csc(x)=sin(x)1​=−sin(x)cos(x)​+cos(x)sin(x)​−cos(x)cos(x)1​+2cos(x)sin(x)1​
化简 −sin(x)cos(x)​+cos(x)sin(x)​−cos(x)cos(x)1​+2cos(x)sin(x)1​:sin(x)cos(x)cos2(x)+sin2(x)−sin(x)cos(x)​
−sin(x)cos(x)​+cos(x)sin(x)​−cos(x)cos(x)1​+2cos(x)sin(x)1​
cos(x)cos(x)1​=1
cos(x)cos(x)1​
分式相乘: a⋅cb​=ca⋅b​=cos(x)1⋅cos(x)​
约分:cos(x)=1
2cos(x)sin(x)1​=sin(x)2cos(x)​
2cos(x)sin(x)1​
分式相乘: a⋅cb​=ca⋅b​=sin(x)1⋅2cos(x)​
数字相乘:1⋅2=2=sin(x)2cos(x)​
=−sin(x)cos(x)​+cos(x)sin(x)​−1+sin(x)2cos(x)​
合并分式 −sin(x)cos(x)​+sin(x)2cos(x)​:sin(x)cos(x)​
使用法则 ca​±cb​=ca±b​=sin(x)−cos(x)+2cos(x)​
同类项相加:−cos(x)+2cos(x)=cos(x)=sin(x)cos(x)​
=sin(x)cos(x)​+cos(x)sin(x)​−1
将项转换为分式: 1=11​=sin(x)cos(x)​+cos(x)sin(x)​−11​
sin(x),cos(x),1的最小公倍数:sin(x)cos(x)
sin(x),cos(x),1
最小公倍数 (LCM)
计算出由至少在以下一个因式表达式中出现的因子组成的表达式=sin(x)cos(x)
根据最小公倍数调整分式
将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值 sin(x)cos(x)
对于 sin(x)cos(x)​:将分母和分子乘以 cos(x)sin(x)cos(x)​=sin(x)cos(x)cos(x)cos(x)​=sin(x)cos(x)cos2(x)​
对于 cos(x)sin(x)​:将分母和分子乘以 sin(x)cos(x)sin(x)​=cos(x)sin(x)sin(x)sin(x)​=sin(x)cos(x)sin2(x)​
对于 11​:将分母和分子乘以 sin(x)cos(x)11​=1⋅sin(x)cos(x)1⋅sin(x)cos(x)​=sin(x)cos(x)sin(x)cos(x)​
=sin(x)cos(x)cos2(x)​+sin(x)cos(x)sin2(x)​−sin(x)cos(x)sin(x)cos(x)​
因为分母相等,所以合并分式: ca​±cb​=ca±b​=sin(x)cos(x)cos2(x)+sin2(x)−sin(x)cos(x)​
=sin(x)cos(x)cos2(x)+sin2(x)−sin(x)cos(x)​
cos(x)sin(x)cos2(x)+sin2(x)−cos(x)sin(x)​=0
g(x)f(x)​=0⇒f(x)=0cos2(x)+sin2(x)−cos(x)sin(x)=0
使用三角恒等式改写
−cos(x)sin(x)+1
使用倍角公式: 2sin(x)cos(x)=sin(2x)sin(x)cos(x)=2sin(2x)​=1−2sin(2x)​
1−2sin(2x)​=0
将 1到右边
1−2sin(2x)​=0
两边减去 11−2sin(2x)​−1=0−1
化简−2sin(2x)​=−1
−2sin(2x)​=−1
在两边乘以 2
−2sin(2x)​=−1
在两边乘以 22(−2sin(2x)​)=2(−1)
化简−sin(2x)=−2
−sin(2x)=−2
两边除以 −1
−sin(2x)=−2
两边除以 −1−1−sin(2x)​=−1−2​
化简sin(2x)=2
sin(2x)=2
−1≤sin(x)≤1x∈R无解

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cos(x)=1.22719cos(a)=(sqrt(5))/55sec^2(x)-5=0,0<= x<2pi2sin(5x)+3=25sin(y)-5=3sin(y)-4
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