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人気のある三角関数 >

x(15)=0+70515cos(25)

解

x (15) = 0 + 705 \cdot 15 \cdot cos (2 5^{\circ})

解

x = 705 cos (2 5^{\circ})

+1

十進法表記

x = 638.94698 \dots

解答ステップ

x (15) = 0 + 705 \cdot 15 cos (2 5^{\circ})

数を乗じる:

705 \cdot 15 = 10575

x (15) = 0 + 10575 cos (2 5^{\circ})

0 + 10575 cos (2 5^{\circ}) = 10575 cos (2 5^{\circ})

x (15) = 10575 cos (2 5^{\circ})

以下で両辺を割る

15

x (15) = 10575 cos (2 5^{\circ})

以下で両辺を割る

15

\frac{x \cdot 15}{15} = \frac{10575 cos ( 2 5 ^{\circ} )}{15}

簡素化

x = 705 cos (2 5^{\circ})

x = 705 cos (2 5^{\circ})

グラフ

人気の例

solvefor t,4r+12s+9t=e^3x-2y+xy+cos(2x+3y)

so l v e f or t, 4 r + 12 s + 9 t = e^{3} x - 2 y + x y + cos (2 x + 3 y)

solvefor i,5sin(x)-2=3(1-sin(x))tan^2(x)

so l v e f or i, 5 sin (x) - 2 = 3 (1 - sin (x)) tan^{2} (x)

solvefor y,(b)y=e^{5x}tan(x^2+2)

so l v e f or y, (b) y = e^{5 x} tan (x^{2} + 2)

1/1+tan(x)+1/1-tan(x)=4

\frac{1}{1} + tan (x) + \frac{1}{1} - tan (x) = 4

(tan^3(a))/(tan(a))=k

\frac{tan ^{3} ( a )}{tan ( a )} = k