cos(θ)= 4/5 ,270<θ<360

Lösung

cos (θ) = \frac{4}{5}, 27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - 0.64350 \dots

Radianten

θ = 2 π - 0.64350 \dots

Schritte zur Lösung

cos (θ) = \frac{4}{5}, 27 0^{\circ} < θ < 36 0^{\circ}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{4}{5}

Allgemeine Lösung für

cos (θ) = \frac{4}{5}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{4}{5}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{4}{5}) + 36 0^{\circ} n

θ = arccos (\frac{4}{5}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{4}{5}) + 36 0^{\circ} n

Lösungen für den Bereich

27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - arccos (\frac{4}{5})

Zeige Lösungen in Dezimalform

θ = 36 0^{\circ} - 0.64350 \dots

tan (\frac{( 5 π )}{6})

sin (\frac{200}{90})

so l v e f or x, tan (x) = 2

so l v e f or x, cos (2 x) = - cos (x)

sin (\frac{( 2 π )}{3})