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Populaire Word Problems >

Rick ran for 3/4 hour on Wednesday for a distance of 4.2 miles. On Thursday, he ran for 1 hour at the same speed he ran on Wednesday. How many miles did Rick run on Thursday?

Solution

R i c k r an f or \frac{3}{4} h o u r o n W e d n es d a y f or a d i s t an ce o f 4.2 mi l es . O n T h u rs d a y, h e r an f or 1 h o u r a t t h e s am e s p ee d h e r an o n W e d n es d a y . Ho w man y mi l es d i d R i c k r u n o n T h u rs d a y ?

Solution

trip 2 distance : 5.6

étapes des solutions

Given Time:

trip 1 : \frac{3}{4}

trip 2 : 1

Given Distance:

trip 1 : 4.2

Represent the speed in terms of

x :

trip 1 : x

trip 1 Speed x Time \frac{3}{4} Distance 4.2

Write an equation for trip 1Distance = Speed

\cdot

Time

4.2 = x \frac{3}{4}

Solutionner pour

x, 4.2 = x \cdot \frac{3}{4} : x = 5.6

speed : 5.6

Represent the distance in terms of

y :

trip 2 : y

trip 2 Speed 5.6 Time 1 Distance y

Write an equation for trip 2Distance = Speed

\cdot

Time

y = 5.6 \cdot 1

Solutionner pour

y, y = 5.6 \cdot 1 : y = 5.6

trip 2 distance : 5.6

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