Mike begins walking toward Thor's house at 3mi/h Thor leaves his house at the same time and walks toward Mike's house on the same path at a rate of 2mi/h How long will it be before they meet if the entfernung between the houses is 4 miles?

Lösung

M ik e b e g in s w a l kin g t o w a r d T h o r^{'} s h o u se a t 3 mi / h T h or l e a v es hi s h o u se a t t h e s am e t im e an d w a l k s t o w a r d M ik e^{'} s h o u se o n t h e s am e p a t h a t a r a t e o f 2 mi / h Ho w l o n g w i ll i t b e b e f ore t h ey m ee t i f t h e d i s t an ce b e tw ee n t h e h o u ses i s 4 mi l es ?

time : \frac{4}{5}

Schritte zur Lösung

Translate the problem into an equation:

3 x + 2 x = 4

Löse nach

x, 3 x + 2 x = 4 : x = \frac{4}{5}

time : \frac{4}{5}