the sum of the square of two consecutive odd integers is equal to 290

解

t h e s u m o f t h e s q u a re o f tw o co n sec u t i v e o dd in t e g ers i s e q u a l t o 290

The numbers : 11, 13 or - 13, - 11

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number : x + 2

A.T.Q.:

x^{2} + (x + 2)^{2} = 290

解く

x^{2} + (x + 2)^{2} = 290 : x = 11, x = - 13

挿入

x = 11 : 13

挿入

x = - 13 : - 11

The numbers : 11, 13 or - 13, - 11