The area of a circle is 64pi in². What is the 円周, in inches? Express your answer in terms of pipi.

解

T h e a re a o f a c i rc l e i s 64 π i n^{2} . Wha t i s t h e c i rc u m f ere n ce, in in c h es ? E x p ress yo u r an s w er in t er m s o f p iπ .

c i rc u m f ere n ce : 2 π \frac{i n ^{2}}{π}

解答ステップ

Given:

a re a : i n^{2}

指定された円の半径

A re a = i n^{2} : r = \frac{n ^{2} i}{π}

指定された円周

r = \frac{i n ^{2}}{π} : C = 2 π \frac{n ^{2} i}{π}

c i rc u m f ere n ce : 2 π \frac{i n ^{2}}{π}