Two airplanes leave at the same time from airports that are 880 miles apart from each other. If one plane travels 126 miles per hour faster than the other and they pass each other in 2 hours, how fast is each plane traveling?

Lösung

Tw o ai r pl an es l e a v e a t t h e s am e t im e f ro m ai r p or t s t ha t a re 880 mi l es a p a r t f ro m e a c h o t h er . I f o n e pl an e t r a v e l s 126 mi l es p er h o u r f a s t er t han t h e o t h er an d t h ey p a ss e a c h o t h er in 2 h o u rs, h o w f a s t i s e a c h pl an e t r a v e l in g ?

first plan e^{'} s speed : 283

second plan e^{'} s speed : 157

Schritte zur Lösung

Translate the problem into an equation:

x \cdot 2 + (x - 126) \cdot 2 = 880

Löse nach

x, x \cdot 2 + (x - 126) \cdot 2 = 880 : x = 283

Finde speed

first plan e^{'} s speed : 283

second plan e^{'} s speed : 157