Two airplanes leave at the same time from airports that are 880 miles apart from each other. If one plane travels 126 miles per hour faster than the other and they pass each other in 2 hours, how fast is each plane traveling?

解

Tw o ai r pl an es l e a v e a t t h e s am e t im e f ro m ai r p or t s t ha t a re 880 mi l es a p a r t f ro m e a c h o t h er . I f o n e pl an e t r a v e l s 126 mi l es p er h o u r f a s t er t han t h e o t h er an d t h ey p a ss e a c h o t h er in 2 h o u rs, h o w f a s t i s e a c h pl an e t r a v e l in g ?

first plan e^{'} s speed : 283

second plan e^{'} s speed : 157

解答ステップ

Translate the problem into an equation:

x \cdot 2 + (x - 126) \cdot 2 = 880

x

を解く

x \cdot 2 + (x - 126) \cdot 2 = 880 : x = 283

発見する speed

first plan e^{'} s speed : 283

second plan e^{'} s speed : 157