Find four consecutive even integers such that if the sum of the first and the third is multiplied by 3, the result is 28 less than 5 times the fourth.

解

F in d f o u r co n sec u t i v e e v e n in t e g ers s u c h t ha t i f t h e s u m o f t h e f i rs t an d t h e t hi r d i s m u lt i pl i e d b y 3, t h e res u lt i s 28 l ess t han 5 t im es t h e f o u r t h .

解なし

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

A.T.Q.:

(x + \frac{1}{3}) \cdot 3 = 5 (x + 6) - 28

解く

(x + \frac{1}{3}) \cdot 3 = 5 (x + 6) - 28 : x = - \frac{1}{2}

x + 2 = - \frac{1}{2} + 2 = \frac{3}{2}

x + 4 = - \frac{1}{2} + 4 = \frac{7}{2}

x + 6 = - \frac{1}{2} + 6 = \frac{11}{2}

Odd value

\frac{3}{2}

discarded

解なし