Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

解

F in d tw o co n sec u t i v e in t e g ers s u c h t ha t t h e s q u a re o f t h e l a r g er in t e g er i s nin t ee n m ore t han nin e t im es t h e s ma ll er in t e g er

The numbers : 9, 10 or - 2, - 1

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number : x + 1

A.T.Q.:

(x + 1)^{2} = 19 + 9 x

解く

(x + 1)^{2} = 19 + 9 x : x = 9, x = - 2

挿入

x = 9 : 10

挿入

x = - 2 : - 1

The numbers : 9, 10 or - 2, - 1