A person invests 7500 dollars in a bank. The bank pays 6% interest compounded semi-annually. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 10100 dollars?

Lösung

A p erso n in v es t s 7500 d o ll a rs in a bank . T h e bank p a ys 6% in t eres t co m p o u n d e d se mi - ann u a ll y . T o t h e n e a res t t e n t h o f a ye a r, h o w l o n g m u s t t h e p erso n l e a v e t h e m o n ey in t h e bank u n t i l i t re a c h es 10100 d o ll a rs ?

Time : 5.03

Schritte zur Lösung

Translate the problem into an equation:

10100 = 7500 (1 + \frac{0.06}{2})^{2 t}

Löse nach

t, 10100 = 7500 (1 + \frac{0.06}{2})^{2 t} : t = 5.03

Time : 5.03