Taylor invested 650 in an account paying an interest rate of 2.3% compounded daily. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach 880?

Lösung

T a y l or in v es t e d 650 in an a cco u n t p a y in g an in t eres t r a t e o f 2.3% co m p o u n d e d d ai l y . A ss u min g n o d e p os i t s or w i t h d r a w a l s a re ma d e, h o w l o n g w o u l d i t t ak e, t o t h e n e a res t t e n t h o f a ye a r, f or t h e v a l u e o f t h e a cco u n t t o re a c h 880 ?

Time : 13.17

Schritte zur Lösung

Translate the problem into an equation:

880 = 650 (1 + \frac{0.023}{365})^{365 t}

Löse nach

t, 880 = 650 (1 + \frac{0.023}{365})^{365 t} : t = 13.17

Time : 13.17