Four consecutive odd integers have a sum of-48. What is the value of the least integer?

解

F o u r co n sec u t i v e o dd in t e g ers ha v e a s u m o f - 48. Wha t i s t h e v a l u e o f t h e l e a s t in t e g er ?

The smallest number : - 15

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

A.T.Q.:

x + x + 2 + x + 4 + x + 6 = - 48

解く

x + x + 2 + x + 4 + x + 6 = - 48 : x = - 15

x + 2 = - 15 + 2 = - 13

x + 4 = - 15 + 4 = - 11

x + 6 = - 15 + 6 = - 9

Select the smallest solution:

- 15

The smallest number : - 15