the sum of the squares of two consecutive integers is 580.

解

t h e s u m o f t h e s q u a res o f tw o co n sec u t i v e in t e g ers i s 580.

The numbers : \frac{- 1 + 1159}{2}, \frac{- 1 + 1159}{2} + 1 or - \frac{1 + 1159}{2}, - \frac{1 + 1159}{2} + 1

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 580

解く

x^{2} + (x + 1)^{2} = 580 : x = \frac{- 1 + 1159}{2}, x = - \frac{1 + 1159}{2}

挿入

x = \frac{- 1 + 1159}{2} : \frac{- 1 + 1159}{2} + 1

挿入

x = - \frac{1 + 1159}{2} : - \frac{1 + 1159}{2} + 1

The numbers : \frac{- 1 + 1159}{2}, \frac{- 1 + 1159}{2} + 1 or - \frac{1 + 1159}{2}, - \frac{1 + 1159}{2} + 1