The sum of 6 consecutive even numbers is 393 .

解

T h e s u m o f 6 co n sec u t i v e e v e n n u mb ers i s 393 .

The numbers : 60 \frac{1}{2}, 62 \frac{1}{2}, 64 \frac{1}{2}, 66 \frac{1}{2}, 68 \frac{1}{2}, 70 \frac{1}{2}

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

Consecutive number 4 : x + 8

Consecutive number 5 : x + 10

A.T.Q.:

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 393

解く

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 393 : x = \frac{121}{2}

x + 2 = \frac{121}{2} + 2 = \frac{125}{2}

x + 4 = \frac{121}{2} + 4 = \frac{129}{2}

x + 6 = \frac{121}{2} + 6 = \frac{133}{2}

x + 8 = \frac{121}{2} + 8 = \frac{137}{2}

x + 10 = \frac{121}{2} + 10 = \frac{141}{2}

仮分数を帯分数に変換する:

\frac{121}{2} = 60 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{125}{2} = 62 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{129}{2} = 64 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{133}{2} = 66 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{137}{2} = 68 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{141}{2} = 70 \frac{1}{2}

The numbers : 60 \frac{1}{2}, 62 \frac{1}{2}, 64 \frac{1}{2}, 66 \frac{1}{2}, 68 \frac{1}{2}, 70 \frac{1}{2}