d/(dr(T))(({E}(r,T))(10-10T(b^{-0.14r(T)})))

Lösung

\frac{d ^{2}}{d r ( T ) d T} ((E (r, T)) (10 - 10 T (b^{- 0.14 r (T)})))

\frac{d}{d T} (E (r, T)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (r, T)

Schritte zur Lösung

\frac{d ^{2}}{d r ( T ) d T} ((E (r, T)) (10 - 10 T (b^{- 0.14 r (T)})))

\frac{d}{d r ( T )} (E (r, T) (10 - 10 T b^{- 0.14 r (T)})) = E (r, T) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b)))

= \frac{d}{d T} (E (r, T) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))))

\frac{d}{d T} (E (r, T) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b)))) = \frac{d}{d T} (E (r, T)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (r, T)

= \frac{d}{d T} (E (r, T)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (r, T)

s im pl i f y (x - i y + 1)^{3}

e x p an d \frac{x ^{2} ( x ^{2} - 3 )}{( x ^{2} - 1 ) ^{2}}

s im pl i f y (7 x - \frac{1}{3}) (7 x + \frac{1}{3})

e x p an d \frac{e ^{(- 3 s) (4 - 8 s)}}{s ^{2} + 64}

s im pl i f y (- 1 + i 3)^{4}