z^2-4z-12=0

解

z^{2} - 4 z - 12 = 0

z = 6, z = - 2

解答ステップ

z^{2} - 4 z - 12 = 0

解くとthe二次式

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

z_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

解を分離する

z_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, z_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

z = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

z = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

二次equationの解:

z = 6, z = - 2