zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor y,2xy-y^2=1

解答

求解

y, 2 x y - y^{2} = 1

解答

y = x - x^{2} - 1, y = x + x^{2} - 1

求解步骤

2 x y - y^{2} = 1

将

1

para o lado esquerdo

2 x y - y^{2} - 1 = 0

改写成标准形式

a x^{2} + b x + c = 0

- y^{2} + 2 x y - 1 = 0

使用求根公式求解

y_{1, 2} = \frac{- 2 x \pm ( 2 x ) ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

化简

(2 x)^{2} - 4 (- 1) (- 1) : 2 x^{2} - 1

y_{1, 2} = \frac{- 2 x \pm 2 x ^{2} - 1}{2 ( - 1 )}

将解分隔开

y_{1} = \frac{- 2 x + 2 x ^{2} - 1}{2 ( - 1 )}, y_{2} = \frac{- 2 x - 2 x ^{2} - 1}{2 ( - 1 )}

y = \frac{- 2 x + 2 x ^{2} - 1}{2 ( - 1 )} : x - x^{2} - 1

y = \frac{- 2 x - 2 x ^{2} - 1}{2 ( - 1 )} : x + x^{2} - 1

二次方程组的解是:

y = x - x^{2} - 1, y = x + x^{2} - 1

作图

流行的例子

6 v^{2} - 30 v = 0

x^{2} - 6 x + 135 = 0

(x+2)^2-(x-2)^2=x^2+7

(x + 2)^{2} - (x - 2)^{2} = x^{2} + 7

(x + 3) (x + 4) = 6

solvefor r,a=2pir^2+2pirh

so l v e f or r, a = 2 π r^{2} + 2 π r h