u^2+7u+12=0

解

u^{2} + 7 u + 12 = 0

u = - 3, u = - 4

解答ステップ

u^{2} + 7 u + 12 = 0

解くとthe二次式

u_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

u_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

解を分離する

u_{1} = \frac{- 7 + 1}{2 \cdot 1}, u_{2} = \frac{- 7 - 1}{2 \cdot 1}

u = \frac{- 7 + 1}{2 \cdot 1} : - 3

u = \frac{- 7 - 1}{2 \cdot 1} : - 4

二次equationの解:

u = - 3, u = - 4