solvefor b,x^2+asqrt(xy)+y^2=b^2

解

解く

b, x^{2} + a x y + y^{2} = b^{2}

b = x^{2} + a x y + y^{2}, b = - x^{2} + a x y + y^{2}

解答ステップ

x^{2} + a x y + y^{2} = b^{2}

辺を交換する

b^{2} = x^{2} + a x y + y^{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

b = x^{2} + a x y + y^{2}, b = - x^{2} + a x y + y^{2}