erweitern (0.4+0.6e^t)^3

Lösung

erweitern

(0.4 + 0.6 e^{t})^{3}

0.064 + 0.288 e^{t} + 0.432 e^{2 t} + 0.216 e^{3 t}

Schritte zur Lösung

(0.4 + 0.6 e^{t})^{3}

Wende Formel für perfekte dritte Potenzen an:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

a = 0.4, b = 0.6 e^{t}

= 0. 4^{3} + 3 \cdot 0. 4^{2} \cdot 0.6 e^{t} + 3 \cdot 0.4 (0.6 e^{t})^{2} + (0.6 e^{t})^{3}

Vereinfache

0. 4^{3} + 3 \cdot 0. 4^{2} \cdot 0.6 e^{t} + 3 \cdot 0.4 (0.6 e^{t})^{2} + (0.6 e^{t})^{3} : 0.064 + 0.288 e^{t} + 0.432 e^{2 t} + 0.216 e^{3 t}

= 0.064 + 0.288 e^{t} + 0.432 e^{2 t} + 0.216 e^{3 t}

e x p an d e^{t} (H (t) - H (t - 1))

\frac{\partial}{\partial x} ((u) (3 x (x - 1)))

e x p an d (5, 6, 8) - (7 i + 6 j)

e x p an d 2 x + y (cos (t)) + (2 y + x) e^{t}

e x p an d \frac{3 ( 2 x - 1 ) ^{2}}{2 x}