erweitern f(x^2-9)\circ g(x^2+3x)

Lösung

erweitern

f (x^{2} - 9) \circ g (x^{2} + 3 x)

\circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

Schritte zur Lösung

f (x^{2} - 9) \circ g (x^{2} + 3 x)

= \circ f g (x^{2} - 9) (x^{2} + 3 x)

Multipliziere aus

(x^{2} - 9) (x^{2} + 3 x) : x^{4} + 3 x^{3} - 9 x^{2} - 27 x

= f \circ g (x^{4} + 3 x^{3} - 9 x^{2} - 27 x)

Multipliziere aus

f \circ g (x^{4} + 3 x^{3} - 9 x^{2} - 27 x) : \circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

= \circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

e x p an d (x^{2} y^{2} + x^{2} + y^{2} + 1) d y

e x p an d \frac{a}{b} (2 x - 12 = \frac{c}{d})

e x p an d \frac{3 π ( 2 + 2 )}{32}

e x p an d (1 - e^{- 2 t})^{2}

e x p an d \frac{2}{( x + 4 ) ^{2}}