2^y=5

Lösung

2^{y} = 5

y = \frac{ln ( 5 )}{ln ( 2 )}

Dezimale

y = 2.32192 \dots

Schritte zur Lösung

2^{y} = 5

Wende Exponentenregel an

y ln (2) = ln (5)

Löse

y ln (2) = ln (5) : y = \frac{ln ( 5 )}{ln ( 2 )}

y = \frac{ln ( 5 )}{ln ( 2 )}

\frac{2 ^{x}}{512} = (2^{x})^{4}

7^{1 - x} = 3^{2 x + 1}

100 = e^{- 9 t + 3 l n (2)}

5^{x} = e^{x - 1}

x^{l o g_{5} (x) - 2} = 125