解答
z4+2i=6+3i
解答
z=837cos(4arctan(61))+837isin(4arctan(61)),z=837cos(4arctan(61)+2π)+837isin(4arctan(61)+2π),z=837cos(4arctan(61)+4π)+837isin(4arctan(61)+4π),z=837cos(4arctan(61)+6π)+837isin(4arctan(61)+6π)
求解步骤
z4+2i=6+3i
将 2i到右边
z4=6+i
For zn=athe solutions are zk=n∣a∣(cos(narg(a)+2kπ)+isin(narg(a)+2kπ)),
k=0,1,…,n−1
对于 n=4,a=6+i∣a∣=37
arg(a)=arctan(61)
z=437(cos(4arctan(61)+2⋅0π)+isin(4arctan(61)+2⋅0π)),z=437(cos(4arctan(61)+2⋅1π)+isin(4arctan(61)+2⋅1π)),z=437(cos(4arctan(61)+2⋅2π)+isin(4arctan(61)+2⋅2π)),z=437(cos(4arctan(61)+2⋅3π)+isin(4arctan(61)+2⋅3π))
化简 437(cos(4arctan(61)+2⋅0π)+isin(4arctan(61)+2⋅0π)):837cos(4arctan(61))+837isin(4arctan(61))
化简 437(cos(4arctan(61)+2⋅1π)+isin(4arctan(61)+2⋅1π)):837cos(4arctan(61)+2π)+837isin(4arctan(61)+2π)
化简 437(cos(4arctan(61)+2⋅2π)+isin(4arctan(61)+2⋅2π)):837cos(4arctan(61)+4π)+837isin(4arctan(61)+4π)
化简 437(cos(4arctan(61)+2⋅3π)+isin(4arctan(61)+2⋅3π)):837cos(4arctan(61)+6π)+837isin(4arctan(61)+6π)
z=837cos(4arctan(61))+837isin(4arctan(61)),z=837cos(4arctan(61)+2π)+837isin(4arctan(61)+2π),z=837cos(4arctan(61)+4π)+837isin(4arctan(61)+4π),z=837cos(4arctan(61)+6π)+837isin(4arctan(61)+6π)