(z^6+1)/(z^2+1)=0

Lösung

\frac{z ^{6} + 1}{z ^{2} + 1} = 0

z = \frac{3}{2} + \frac{1}{2} i, z = - \frac{3}{2} - \frac{1}{2} i, z = \frac{3}{2} - \frac{1}{2} i, z = - \frac{3}{2} + \frac{1}{2} i

Schritte zur Lösung

\frac{z ^{6} + 1}{z ^{2} + 1} = 0

Vereinfache

\frac{z ^{6} + 1}{z ^{2} + 1} : z^{4} - z^{2} + 1

z^{4} - z^{2} + 1 = 0

Löse

z^{4} - z^{2} + 1 = 0 : z = \frac{3}{2} + \frac{1}{2} i, z = - \frac{3}{2} - \frac{1}{2} i, z = \frac{3}{2} - \frac{1}{2} i, z = - \frac{3}{2} + \frac{1}{2} i

z = \frac{3}{2} + \frac{1}{2} i, z = - \frac{3}{2} - \frac{1}{2} i, z = \frac{3}{2} - \frac{1}{2} i, z = - \frac{3}{2} + \frac{1}{2} i

12 x - \frac{288}{x ^{2}} = 0

1 - \frac{8}{x ^{2} + 6 x} = - \frac{x}{x + 6}

\frac{7 x - 1}{x ^{2} + 9} = 1

\frac{5 x}{x - 3} - 1 = - \frac{1}{x - 3}

19.11969 = 19.62 x + (\frac{1.5}{3 x})^{2}