2^{5-7x}=15

Lösung

2^{5 - 7 x} = 15

x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

Dezimale

x = 0.15615 \dots

Schritte zur Lösung

2^{5 - 7 x} = 15

Wende Exponentenregel an

(5 - 7 x) ln (2) = ln (15)

Löse

(5 - 7 x) ln (2) = ln (15) : x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

4^{x^{2} + 1} = 2^{5 x + 5}

x^{3} = 1. 5^{x}

4^{x + 2} - 3 \times 2^{x + 3} = 160

3 (5^{x - 1}) = 21

4 \cdot 1 0^{2 - x} = 15