5^{x+1}=7

Lösung

5^{x + 1} = 7

x = \frac{ln ( 7 )}{ln ( 5 )} - 1

Dezimale

x = 0.20906 \dots

Schritte zur Lösung

5^{x + 1} = 7

Wende Exponentenregel an

(x + 1) ln (5) = ln (7)

Löse

(x + 1) ln (5) = ln (7) : x = \frac{ln ( 7 )}{ln ( 5 )} - 1

x = \frac{ln ( 7 )}{ln ( 5 )} - 1

2 e^{2 x} = 97

2 = 2^{t} - 2 t

6 x e^{x} + 5 e^{x + 2} = 0

3^{x} = 5^{x - 1}

e^{x} e^{2} = \frac{e ^{4}}{e ^{x + 1}}