2^{3x+1}=3^{2-x}

Lösung

2^{3 x + 1} = 3^{2 - x}

x = \frac{2 ln ( 3 ) - ln ( 2 )}{ln ( 24 )}

Dezimale

x = 0.47326 \dots

Schritte zur Lösung

2^{3 x + 1} = 3^{2 - x}

Wende Exponentenregel an

(3 x + 1) ln (2) = (2 - x) ln (3)

Löse

(3 x + 1) ln (2) = (2 - x) ln (3) : x = \frac{2 ln ( 3 ) - ln ( 2 )}{ln ( 24 )}

x = \frac{2 ln ( 3 ) - ln ( 2 )}{ln ( 24 )}

\frac{1}{6} = 6^{x}

7^{3 x - 3} = 343

e^{x} - e^{- x} = - 1

4^{x - 5} = 8^{2 x - 2}

\frac{2 ^{8 - x}}{3 2 ^{x + 12}} = 2^{3 x - 7}