5e^{0.01t}=2e^{0.02t}

Lösung

5 e^{0.01 t} = 2 e^{0.02 t}

t = \frac{ln ( 5 ) - ln ( 2 )}{0.01}

Dezimale

t = 91.62907 \dots

Schritte zur Lösung

5 e^{0.01 t} = 2 e^{0.02 t}

Wende Exponentenregel an

ln (5) + 0.01 t = ln (2) + 0.02 t

Löse

ln (5) + 0.01 t = ln (2) + 0.02 t : t = \frac{ln ( 5 ) - ln ( 2 )}{0.01}

t = \frac{ln ( 5 ) - ln ( 2 )}{0.01}

4 9^{3 x} = \frac{1}{343}

92 \cdot 3^{4 x} = 27

(x) = 2^{x + 1} - 3

4 (2^{x} + 2^{- x}) = 17

6^{x + 1} = 216