quadraticformula (x-6)(x+2)=0

解

(x - 6) (x + 2) = 0

x = 6, x = - 2

解答ステップ

(x - 6) (x + 2) = 0

拡張

(x - 6) (x + 2) : x^{2} - 4 x - 12

x^{2} - 4 x - 12 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

二次equationの解:

x = 6, x = - 2