What is the solution for (dy)/(dt)=-2(1+y^2)tan(2t) ?

The solution for (dy)/(dt)=-2(1+y^2)tan(2t) is y=tan(ln(cos(2t))+c_{1})

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(dy)/(dt)=-2(1+y^2)tan(2t)

\frac{d y}{d t} = - 2 (1 + y^{2}) tan (2 t)

y = tan (ln (cos (2 t)) + c_{1})

Solution steps

\frac{d y}{d t} = - 2 (1 + y^{2}) tan (2 t)

Solve separable ODE:

y = tan (ln (cos (2 t)) + c_{1})

y = tan (ln (cos (2 t)) + c_{1})

What is the solution for (dy)/(dt)=-2(1+y^2)tan(2t) ?
The solution for (dy)/(dt)=-2(1+y^2)tan(2t) is y=tan(ln(cos(2t))+c_{1})