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Popular Calculus >

integral from 15 to 35 of (x^2x)

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Solution

∫1535​(x2x)dx

Solution

362500
Solution steps
∫1535​x2xdx
Simplify x2x:x3
=∫1535​x3dx
Apply the Power Rule
=[4x4​]1535​
Compute the boundaries:362500
=362500

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Popular Examples

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Frequently Asked Questions (FAQ)

  • What is the integral from 15 to 35 of (x^2x) ?

    The integral from 15 to 35 of (x^2x) is 362500
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