What is the solution for (dy)/(dt)= y/(t+1)+4t^2+4t,y(1)=6 ?

The solution for (dy)/(dt)= y/(t+1)+4t^2+4t,y(1)=6 is y=2t^2(t+1)+t+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dt)= y/(t+1)+4t^2+4t,y(1)=6

\frac{d y}{d t} = \frac{y}{t + 1} + 4 t^{2} + 4 t, y (1) = 6

y = 2 t^{2} (t + 1) + t + 1

Solution steps

\frac{d y}{d t} = \frac{y}{t + 1} + 4 t^{2} + 4 t

Solve linear ODE:

y = 2 t^{2} (t + 1) + t + 1

y = 2 t^{2} (t + 1) + t + 1

What is the solution for (dy)/(dt)= y/(t+1)+4t^2+4t,y(1)=6 ?
The solution for (dy)/(dt)= y/(t+1)+4t^2+4t,y(1)=6 is y=2t^2(t+1)+t+1