What is the derivative of f(x)=(x^5-4x^3-7)^8 ?

The derivative of f(x)=(x^5-4x^3-7)^8 is 8(x^5-4x^3-7)^7(5x^4-12x^2)

What is the first derivative of f(x)=(x^5-4x^3-7)^8 ?

The first derivative of f(x)=(x^5-4x^3-7)^8 is 8(x^5-4x^3-7)^7(5x^4-12x^2)

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derivative of

f (x) = (x^{5} - 4 x^{3} - 7)^{8}

8 (x^{5} - 4 x^{3} - 7)^{7} (5 x^{4} - 12 x^{2})

Solution steps

\frac{d}{d x} ((x^{5} - 4 x^{3} - 7)^{8})

Apply the chain rule:

8 (x^{5} - 4 x^{3} - 7)^{7} \frac{d}{d x} (x^{5} - 4 x^{3} - 7)

= 8 (x^{5} - 4 x^{3} - 7)^{7} \frac{d}{d x} (x^{5} - 4 x^{3} - 7)

\frac{d}{d x} (x^{5} - 4 x^{3} - 7) = 5 x^{4} - 12 x^{2}

= 8 (x^{5} - 4 x^{3} - 7)^{7} (5 x^{4} - 12 x^{2})

What is the derivative of f(x)=(x^5-4x^3-7)^8 ?
The derivative of f(x)=(x^5-4x^3-7)^8 is 8(x^5-4x^3-7)^7(5x^4-12x^2)
What is the first derivative of f(x)=(x^5-4x^3-7)^8 ?
The first derivative of f(x)=(x^5-4x^3-7)^8 is 8(x^5-4x^3-7)^7(5x^4-12x^2)