What is area 7cos(8x),7-7cos(8x),[0, pi/8 ] ?

The answer to area 7cos(8x),7-7cos(8x),[0, pi/8 ] is (7pi+42sqrt(3))/(24)

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area 7cos(8x),7-7cos(8x),[0, pi/8 ]

area

7 cos (8 x), 7 - 7 cos (8 x), [0, \frac{π}{8}]

\frac{7 π + 42 3}{24}

Decimal

3.94738 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{8}} ∣ 7 cos (8 x) - (7 - 7 cos (8 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{8}} ∣ 7 cos (8 x) - (7 - 7 cos (8 x)) ∣ d x : \frac{7 π + 42 3}{24}

The area is:

= \frac{7 π + 42 3}{24}

What is area 7cos(8x),7-7cos(8x),[0, pi/8 ] ?
The answer to area 7cos(8x),7-7cos(8x),[0, pi/8 ] is (7pi+42sqrt(3))/(24)