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Popular Calculus >

integral of 3picos^3(5pix)sin^7(5pix)

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Solution

∫3πcos3(5πx)sin7(5πx)dx

Solution

53​(−41​cos4(5πx)+21​cos6(5πx)−83​cos8(5πx)+101​cos10(5πx))+C
Solution steps
∫3πcos3(5πx)sin7(5πx)dx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=3π⋅∫cos3(5πx)sin7(5πx)dx
Apply u-substitution
=3π⋅∫cos3(u)sin7(u)5π1​du
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=3π5π1​⋅∫cos3(u)sin7(u)du
Rewrite using trig identities
=3π5π1​⋅∫(1−cos2(u))3sin(u)cos3(u)du
Apply u-substitution
=3π5π1​⋅∫−v3(1−v2)3dv
Expand −v3(1−v2)3:−v3+3v5−3v7+v9
=3π5π1​⋅∫−v3+3v5−3v7+v9dv
Apply the Sum Rule: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=3π5π1​(−∫v3dv+∫3v5dv−∫3v7dv+∫v9dv)
∫v3dv=4v4​
∫3v5dv=2v6​
∫3v7dv=83v8​
∫v9dv=10v10​
=3π5π1​(−4v4​+2v6​−83v8​+10v10​)
Substitute back
=3π5π1​(−4cos4(5πx)​+2cos6(5πx)​−83cos8(5πx)​+10cos10(5πx)​)
Simplify 3π5π1​(−4cos4(5πx)​+2cos6(5πx)​−83cos8(5πx)​+10cos10(5πx)​):53​(−41​cos4(5πx)+21​cos6(5πx)−83​cos8(5πx)+101​cos10(5πx))
=53​(−41​cos4(5πx)+21​cos6(5πx)−83​cos8(5πx)+101​cos10(5πx))
Add a constant to the solution=53​(−41​cos4(5πx)+21​cos6(5πx)−83​cos8(5πx)+101​cos10(5πx))+C

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