(dy)/(dx)=(x+y)^2-1,y(3)=4

Lösung

\frac{d y}{d x} = (x + y)^{2} - 1, y (3) = 4

y = - \frac{7}{7 x - 22} - x

Schritte zur Lösung

\frac{d y}{d x} = (x + y)^{2} - 1

Solve using substitution:

y = - \frac{7}{7 x - 22} - x

y = - \frac{7}{7 x - 22} - x

\int_{0}^{1} 2 (1 + x)^{8} d x

d er i v a t i v e \frac{( x + 2 )}{( x - 2 )}

x \to 3 lim (\frac{2 ^{x} - 8}{3 - x})

a re a y = 4 x, y = 4, y = \frac{4}{9} x^{2} 4

\int_{6}^{8} \frac{62}{( x - 6 ) ^{3}} d x