What is the integral from 2 to infinity of ye^{-9y} ?

The integral from 2 to infinity of ye^{-9y} is (19)/(81e^{18)}

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integral from 2 to infinity of ye^{-9y}

\int_{2}^{\infty} y e^{- 9 y} d y

\frac{19}{81 e ^{18}}

Decimal

3.57246 E - 9

Solution steps

\int_{2}^{\infty} y e^{- 9 y} d y

Compute the indefinite integral:

\int y e^{- 9 y} d y = \frac{1}{81} (- 9 e^{- 9 y} y - e^{- 9 y}) + C

Compute the boundaries:

\int_{2}^{\infty} y e^{- 9 y} d y = 0 - (- \frac{19}{81 e ^{18}})

= 0 - (- \frac{19}{81 e ^{18}})

Simplify

= \frac{19}{81 e ^{18}}

What is the integral from 2 to infinity of ye^{-9y} ?
The integral from 2 to infinity of ye^{-9y} is (19)/(81e^{18)}