What is the tangent of f(x)=5x^3-5x,(1,0) ?

The tangent of f(x)=5x^3-5x,(1,0) is y=10x-10

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tangent of f(x)=5x^3-5x,(1,0)

tangent of

f (x) = 5 x^{3} - 5 x, (1, 0)

y = 10 x - 10

Solution steps

Find the slope of

f (x) = 5 x^{3} - 5 x : \frac{df ( x )}{d x} = 15 x^{2} - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(1, 0) : y = 10 x - 10

y = 10 x - 10

What is the tangent of f(x)=5x^3-5x,(1,0) ?
The tangent of f(x)=5x^3-5x,(1,0) is y=10x-10