What is the integral of sin(x)e^{2x} ?

The integral of sin(x)e^{2x} is -(e^{2x}cos(x))/5+(2e^{2x}sin(x))/5+C

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integral of sin(x)e^{2x}

\int sin (x) e^{2 x} d x

- \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5} + C

Solution steps

\int sin (x) e^{2 x} d x

Apply Integration By Parts

= - e^{2 x} cos (x) - \int - 2 e^{2 x} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 x} cos (x) - (- 2 \cdot \int e^{2 x} cos (x) d x)

Apply Integration By Parts

= - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - \int e^{2 x} \cdot 2 sin (x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - 2 \cdot \int e^{2 x} sin (x) d x))

Therefore

\int e^{2 x} sin (x) d x = - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - 2 \cdot \int e^{2 x} sin (x) d x))

Isolate

\int e^{2 x} sin (x) d x

= - \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5}

Add a constant to the solution

= - \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5} + C

What is the integral of sin(x)e^{2x} ?
The integral of sin(x)e^{2x} is -(e^{2x}cos(x))/5+(2e^{2x}sin(x))/5+C